TS EAMCET · Maths · Permutation Combination
In an admission test, there are 15 multiple choice questions. Each question is followed by 4 alternatives to choose. Out of these there may be one or more than one correct answers. If a student attempts all the 15 questions and marks the answers randomly, then number of different ways he can answer the question paper is
- A \({ }^{4 \times 15} \mathrm{C}_4\)
- B \(15^{15}\)
- C \(4^{15}\)
- D \(4 ! \cdot 15 !\)
Answer & Solution
Correct Answer
(B) \(15^{15}\)
Step-by-step Solution
Detailed explanation
These are 15 multiple type questions. Students attempts all 15 questions. The number of way student can answer the questions is \(=m^n\) \[ \begin{aligned} m & =15 \\ n & =15 \Rightarrow(15)^{15} \end{aligned} \]
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