TS EAMCET · Maths · Properties of Triangles
In a triangle \(\mathrm{ABC}\), if \(\frac{a}{\tan \mathrm{A}}=\frac{b}{\tan \mathrm{B}}=\frac{c}{\tan \mathrm{C}}\) then \(\cos ^2 \mathrm{~A}+\cos ^2 \mathrm{~B}+\cos ^2 \mathrm{C}=\)
- A \(\sqrt{2}\)
- B \(\frac{3}{4}\)
- C \(\frac{\sqrt{3}+1}{2}\)
- D \(\frac{2 \sqrt{3}-1}{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{3}{4}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { } \frac{\mathrm{a}}{\tan \mathrm{A}}=\frac{\mathrm{b}}{\tan \mathrm{B}}=\frac{\mathrm{c}}{\tan \mathrm{C}} \\ & \Rightarrow \frac{\mathrm{a} \cos \mathrm{A}}{\sin \mathrm{A}}=\frac{\mathrm{b} \cos \mathrm{B}}{\sin \mathrm{B}}=\frac{\mathrm{c} \cos…
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