TS EAMCET · Maths · Properties of Triangles
In a triangle \(\mathrm{ABC}, \mathrm{AD}\) and \(\mathrm{BE}\) are medians. If \(\mathrm{AD}=4\), \(\left\lfloor\mathrm{DAB}=\frac{\pi}{6}\right.\) and \(\left\lfloor\mathrm{ABE}=\frac{\pi}{3}\right.\) then the area of \(\triangle \mathrm{ABC}\) is
- A \(\frac{14}{3 \sqrt{3}}\)
- B \(\frac{28}{3 \sqrt{3}}\)
- C \(\frac{11}{3 \sqrt{3}}\)
- D \(\frac{32}{3 \sqrt{3}}\)
Answer & Solution
Correct Answer
(D) \(\frac{32}{3 \sqrt{3}}\)
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