TS EAMCET · Maths · Quadratic Equation
In \(\triangle A B C\), the value of \(\angle A\) is obtained from the equation \(3 \cos A+2=0\). The quadratic equation, whose roots are \(\sin A\) and \(\tan A\), is
- A \(3 x^2+\sqrt{5} x-5=0\)
- B \(6 x^2-\sqrt{5} x-5=0\)
- C \(6 x^2+\sqrt{5} x-5=0\)
- D \(6 x^2+\sqrt{5} x+5=0\)
Answer & Solution
Correct Answer
(C) \(6 x^2+\sqrt{5} x-5=0\)
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