TS EAMCET · Maths · Differentiation
If \(\tan y=\cot \left(\frac{\pi}{4}-x\right)\) then \(\frac{d y}{d x}=\)
- A \(\frac{\operatorname{cosec}^2\left(\frac{\pi}{4}-x\right)}{1+\cot ^2\left(\frac{\pi}{4}+x\right)}\)
- B \(\frac{-\operatorname{cosec}^2\left(\frac{\pi}{4}-x\right)}{\sec ^2 y}\)
- C \(\frac{\operatorname{cosec}^2\left(\frac{\pi}{4}-x\right)}{1+\tan ^2\left(\frac{\pi}{4}-x\right)}\)
- D \(\frac{\sec ^2\left(\frac{\pi}{4}+x\right)}{1+\tan ^2\left(\frac{\pi}{4}+x\right)}\)
Answer & Solution
Correct Answer
(D) \(\frac{\sec ^2\left(\frac{\pi}{4}+x\right)}{1+\tan ^2\left(\frac{\pi}{4}+x\right)}\)
Step-by-step Solution
Detailed explanation
\(\tan y=\cot \left(\frac{\pi}{4}-x\right)\) \(\begin{aligned} \Rightarrow \quad \sec ^2 y \frac{d y}{d x}=-(-1) \operatorname{cosec}^2\left(\frac{\pi}{4}-x\right) \end{aligned}\)…
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