TS EAMCET · Maths · Differentiation
If \(y=\tan \left(\cos ^{-1} x\right)\), then \(\frac{d y}{d x}\) is equal to
- A \(\frac{-x^2}{\sqrt{1-x^2}}\)
- B \(\frac{-1}{\sqrt{1-x^2}}\)
- C \(\frac{-1}{x \sqrt{1-x^2}}\)
- D \(\frac{-1}{x^2 \sqrt{1-x^2}}\)
Answer & Solution
Correct Answer
(D) \(\frac{-1}{x^2 \sqrt{1-x^2}}\)
Step-by-step Solution
Detailed explanation
\(y=\tan \left(\cos ^{-1} x\right)\)…
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