TS EAMCET · Maths · Sequences and Series
If \(x+y=60, x>0, y>0\), then the maximum value of \(x y^3\) is
- A \((15)^4 \frac{25}{3}\)
- B \(45(15)^3\)
- C \(\frac{(45)^3 9}{5}\)
- D \(\frac{(45)^4}{3}\)
Answer & Solution
Correct Answer
(D) \(\frac{(45)^4}{3}\)
Step-by-step Solution
Detailed explanation
Given, \(x+y=60\) By \(\mathrm{AM} \geq \mathrm{GM}\)…
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