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TS EAMCET · Maths · Quadratic Equation

If \(\frac{x^2+x+1}{x^2+2 x+1}=A+\frac{B}{x+1}+\frac{C}{(x+1)^2}\), then \(A-B\) is equal to

  1. A \(4 C\)
  2. B \(4 C+1\)
  3. C \(3 C\)
  4. D \(2 C\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(2 C\)

Step-by-step Solution

Detailed explanation

\[ \frac{x^2+x+1}{x^2+2 x+1}=1-\frac{x}{x^2+2 x+1} \] Now, \(\frac{x}{x^2+2 x+1}=\frac{A}{(x+1)}+\frac{B}{(x+1)^2}\) \[ \Rightarrow \quad x=A(x+1)+B \] On equating the coefficient of \(x\) and constant, we get…
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