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TS EAMCET · Maths · Basic of Mathematics

If \(\frac{x^2-2}{\left(x^2+1\right)\left(x^2+3\right)}=\frac{\mathrm{A} x+\mathrm{B}}{x^2+1}+\frac{\mathrm{C} x+\mathrm{D}}{x^2+3}\) then \(\mathrm{D}=\)

  1. A \(\frac{-3}{2}\)
  2. B \(\frac{-1}{2}\)
  3. C 2
  4. D \(\frac{5}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{5}{2}\)

Step-by-step Solution

Detailed explanation

We have \(\frac{x^2-2}{\left(x^2+1\right)\left(x^2+3\right)}=\frac{A k+B}{x^2+1}+\frac{C x+D}{x^2+3}\) Let \(x^2=y\), we have \(\frac{\mathrm{y}-2}{(\mathrm{y}+1)(\mathrm{y}+3)}=\frac{\mathrm{B}}{\mathrm{y}+1}+\frac{\mathrm{D}}{\mathrm{y}+3}\) For D use…