TS EAMCET · Maths · Quadratic Equation
\(\alpha\) and \(\beta\) are the roots of \(x^2+2 x+c=0\). If \(\alpha^3+\beta^3=4\), then the value of \(c\) is
- A -2
- B 3
- C 2
- D 4
Answer & Solution
Correct Answer
(C) 2
Step-by-step Solution
Detailed explanation
Given, \(\alpha\) and \(\beta\) are the roots of \(x^2+2 x+c=0\). \(\therefore\) Sum of roots, \(\alpha+\beta=\frac{- \text { coefficient of } x}{\text { coefficient of } x^2}\) \(\Rightarrow \quad \alpha+\beta=\frac{-2}{1}=-2\) and Product of roots,…
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