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TS EAMCET · Maths · Straight Lines

If the vertices of a triangle ABC are A(1, 7), B(-5, -1) and C(7, 4), then the equation of a bisector of ABC is

  1. A 7x-9y+26=0
  2. B 9x-7y+38=0
  3. C 7x+9y+44=0
  4. D 9x+7y+52=0
Verified Solution

Answer & Solution

Correct Answer

(A) 7x-9y+26=0

Step-by-step Solution

Detailed explanation

A1,7, B-5,-1, C7,4 Then the bisector of angle B meets side AC at D then ADDC=BABC By using distance formula, BA2=36+64=100⇒BA=10 BC2=7--52+4--12=144+25=169 ⇒BC=13 So ADDC=1013 Hence D8323,13123 Then the equation of a bisector of angle ∠ABC is…
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