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TS EAMCET · Maths · Properties of Triangles

If the sides of a triangle are in the ratio \(\sqrt{3}: \sqrt{5}: \sqrt{8+\sqrt{15}}\), then the largest angle in that triangle is

  1. A \(\frac{2 \pi}{3}\)
  2. B \(\frac{\pi}{2}\)
  3. C \(\frac{\pi}{3}\)
  4. D \(\frac{5 \pi}{6}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{2 \pi}{3}\)

Step-by-step Solution

Detailed explanation

Ratio of sides of triangle are \(\sqrt{3}: \sqrt{5}: \sqrt{8+\sqrt{15}}\) Let sides of triangle are \(\sqrt{3} k, \sqrt{5} k, \sqrt{8+\sqrt{15}} k\) Longest sides is \(\sqrt{8+\sqrt{15} k}\) Let \(\theta\) is longest angle…