TS EAMCET · Maths · Straight Lines
If the lines \(x+3 y-5=0,5 x+2 y-12=0\) and \(3 x-k y-1=0\) do not form a triangle, then a value of \(k\) is
- A \(\frac{1}{5}\)
- B \(\frac{-1}{5}\)
- C \(\frac{-6}{5}\)
- D \(\frac{6}{5}\)
Answer & Solution
Correct Answer
(C) \(\frac{-6}{5}\)
Step-by-step Solution
Detailed explanation
The lines \[ \begin{array}{r} x+3 y-5=0 \\ 5 x+2 y-12=0 \\ 3 x-k y-1=0 \end{array} \] do not form a triangle line (ii) and (iii) are parallel…
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