TS EAMCET · Maths · Binomial Theorem
\(\frac{1}{8}-\frac{7}{8.12}+\frac{7.10}{8.12 .16}-\ldots=\)
- A \(\sqrt[3]{\frac{4}{7}}\)
- B \(\sqrt[3]{\frac{4}{7}}-\frac{3}{4}\)
- C \(\sqrt[3]{\frac{4}{7}}+\frac{3}{4}\)
- D \(\sqrt[3]{\frac{7}{4}}-\frac{3}{4}\)
Answer & Solution
Correct Answer
(B) \(\sqrt[3]{\frac{4}{7}}-\frac{3}{4}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \left(\frac{4}{7}\right)^{\frac{1}{3}}=\left(\frac{7}{4}\right)^{-\frac{1}{3}}=\left(1+\frac{3}{4}\right)^{\frac{-1}{3}} \\ & =1-\frac{1}{3} \times \frac{3}{4}+\frac{\left(-\frac{1}{3}\right)\left(-\frac{1}{3}-1\right)}{2…
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