TS EAMCET · Maths · Quadratic Equation
If one root of the equation \(x^3-9 x^2+26 x-24=0\) is twice the other. Then, the sum of the cubes of those two roots is
- A 72
- B 253
- C 9
- D \(\frac{9}{64}\)
Answer & Solution
Correct Answer
(A) 72
Step-by-step Solution
Detailed explanation
If \(\alpha, \beta\) and \(\gamma\) are the roots of \(x^3-9 x^2+26 x-24=0\) such that \(\alpha=2 \beta\). Clearly, \(\alpha+\beta+\gamma=9, \alpha \beta+\beta \gamma+\gamma \alpha=-26\) and \(\alpha \beta \gamma=24\)…
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