TS EAMCET · Maths · Circle
If the inverse of \(\mathrm{P}(-3,5)\) with respect to a circle is \((1,3)\), then polar of \(\mathrm{P}\) with respect to that circle is
- A \(x+2y=7\)
- B \(2 x-2 y+4=0\)
- C \(2 x-y+1=0\)
- D \(2 x+y-5=0\)
Answer & Solution
Correct Answer
(C) \(2 x-y+1=0\)
Step-by-step Solution
Detailed explanation
Inverse of \(P(-3,5)\) w.r.t. circle is \(A(1,3)\). \(\therefore \quad\) Slope of \(P A: \frac{3-5}{1+3}=\frac{-1}{2}\) \(\therefore\) Slope of polar \(=2\) \(\therefore \quad\) Equation of polar of \(P\) \(\begin{aligned} & y-3=2(x-1) \\ & \Rightarrow 2 x-y+1=0 \end{aligned}\)
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