TS EAMCET · Maths · Properties of Triangles
In a triangle \(A B C\), if \((a-b)^2 \cos ^2 \frac{C}{2}+(a+b)^2 \sin ^2 \frac{C}{2}=a^2+b^2\), then \(\cos A=\)
- A \(\cos \mathrm{B}\)
- B \(\sin \mathrm{C}\)
- C \(\sin \mathrm{B}\)
- D \(\cos C\)
Answer & Solution
Correct Answer
(C) \(\sin \mathrm{B}\)
Step-by-step Solution
Detailed explanation
\((a-b)^2 \cos ^2 \frac{C}{2}+(a+b)^2 \sin ^2 \frac{C}{2}=a^2+b^2\)…
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