TS EAMCET · Maths · Three Dimensional Geometry
If the equation of the plane passing through the points \((2,1,2),(1,2,1)\) and perpendicular to the plane \(2 x-y+2 z=1\) is \(a x+b y+c z+d=0\) then \(\frac{a+b}{c+d}=\)
- A \(0\)
- B \(1\)
- C \(-1\)
- D \(2\)
Answer & Solution
Correct Answer
(C) \(-1\)
Step-by-step Solution
Detailed explanation
Vector through points: \(\vec{v} = (1-2)\mathbf{i} + (2-1)\mathbf{j} + (1-2)\mathbf{k} = -\mathbf{i} + \mathbf{j} - \mathbf{k}\) Normal of perpendicular plane: \(\vec{n_p} = 2\mathbf{i} - \mathbf{j} + 2\mathbf{k}\) Normal of required plane:…
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