TS EAMCET · Maths · Three Dimensional Geometry
If the direction cosines of two lines are such that \(l+m+n=0, l^2+m^2-n^2=0\), then the angle between them is
- A \(\frac{\pi}{6}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{3}\)
- D \(\frac{\pi}{2}\)
Answer & Solution
Correct Answer
(C) \(\frac{\pi}{3}\)
Step-by-step Solution
Detailed explanation
Given that, \[ \begin{array}{cc} & l+m+n=0 \\ \Rightarrow & l+m=-n \\ \Rightarrow & -(l+m=n \\ \text { and } & l^2+m^2-n^2=0 \end{array} \] Let us substitute per ' \(n\) ' in Eq. (ii), we get \[ \Rightarrow l^2+m^2-l^2-m^2-2 m l=0 \Rightarrow 2 m l=0 \] i.e. either \(l=0\) or…
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