TS EAMCET · Maths · Statistics
If the coefficients of variation of two distributions are 40 and 20 and their variances are 144 and 64 respectively, then the mean of their arithmetic means is
- A 40
- B 12
- C 30
- D 35
Answer & Solution
Correct Answer
(D) 35
Step-by-step Solution
Detailed explanation
Let \(\bar{x}_1, \bar{x}_2\) be the means and \(\sigma_1^2, \sigma_2^2\) be the variances of two distributions. Then, we have, \(\sigma_1^2=144, \sigma_2^2=64\), \[ \frac{\sigma_1}{\bar{x}_1} \times 100=40 \text { and } \frac{\sigma_2}{\bar{x}_2} \times 100=20 \] Now,…
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