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TS EAMCET · Maths · Circle

If the circles given by Sx2+y2-14x+6y+33=0 and S'x2+y2-a2=0 aN have 4 common tangents, then the possible number of circles S'=0 is

  1. A 1
  2. B 2
  3. C 0
  4. D infinite
Verified Solution

Answer & Solution

Correct Answer

(B) 2

Step-by-step Solution

Detailed explanation

Given circles are S1≡x2+y2-14x+6y+33=0 S2≡x2+y2-a2=0 Here, r1+r2<c1c2 as the circles have 4 common tangents. c1=7,-3; c2=0,0 c1c2=7-02+-3-02=72+32=49+9=58 r1=72+32-33=49+9-33=25=5 r2=a2=a r2+r2=5+a<58 ⇒5+a2<58 The above equation satisfies for…