TS EAMCET · Maths · Properties of Triangles
If \(R: r_1: r=5: 12: 2\), then \(r+r_3+r_2-r_1=\)
- A \(\cos A\)
- B \(\sin A\)
- C \(2 r r_1\)
- D \(2 r_1^2 r\)
Answer & Solution
Correct Answer
(A) \(\cos A\)
Step-by-step Solution
Detailed explanation
We have, \(R: r_1: r: 5: 12: 2\) \(\therefore R=5 k, r_1=12 k, r=2 k\) If \(\triangle A B C\) is right angle of \(A\) and \(a=10 k, b=6 k, c=8 k\) Then \(R=5 k, r_1=12 k\) and \(r=2 k\) Possible \(\therefore \quad a^2=b^2+c^2\) \(\therefore \quad r+r_3+r_2-r_1\)…
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