TS EAMCET · Maths · Application of Derivatives
If \(Q\) is the point on the parabola \(y^2=4 x\) that is nearest to the point \(P(2,0)\), then \(P Q=\)
- A 1
- B 2
- C 3
- D 4
Answer & Solution
Correct Answer
(B) 2
Step-by-step Solution
Detailed explanation
Let \(Q\) be \((x, y)\) \[ \begin{array}{lll} \therefore & P Q=\sqrt{(x-2)^2+(y-0)^2} & \\ \Rightarrow & P Q=\sqrt{(x-2)^2+y^2} & \\ \Rightarrow & P Q=\sqrt{\left(x-4^2+4 x\right.} & {\left[\because y^2=4 x\right]} \\ \Rightarrow & P Q=\sqrt{x^2+4} & \end{array} \] For minimum…
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