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TS EAMCET · Maths · Properties of Triangles

If d1, d2, d3 are the diameters of three ex-circles of a ΔABC, then d1d2+d2d3+d3d1=

  1. A a+b+c2
  2. B ab+bc+ca
  3. C 4Δ2
  4. D 4s3
Verified Solution

Answer & Solution

Correct Answer

(A) a+b+c2

Step-by-step Solution

Detailed explanation

We know d1=2∆s-a, d2=2∆s-b, d3=2∆s-c ⇒d1d2+d2d3+d3d1=4∆23s-a+b+cs-as-bs-c =4∆2×s×sss-as-bs-c=4s2=(a+b+c)2