TS EAMCET · Maths · Vector Algebra
If \(\quad \overrightarrow{\mathbf{a}}=\hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}}, \quad \overrightarrow{\mathbf{b}}=\hat{\mathbf{i}}+\hat{\mathbf{j}}, \quad \overrightarrow{\mathbf{c}}=\hat{\mathbf{i}} \quad\) and \((\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{b}}) \times \overrightarrow{\mathbf{c}}=\lambda \overrightarrow{\mathbf{a}}+\mu \overrightarrow{\mathbf{b}}\), then \(\lambda+\mu\) is equal to:
- A 0
- B 1
- C 1
- D 3
Answer & Solution
Correct Answer
(A) 0
Step-by-step Solution
Detailed explanation
We have \(\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{b}}=\left|\begin{array}{ccc}\hat{\mathbf{i}} & \hat{\mathbf{j}} & \hat{\mathbf{k}} \\ 1 & 1 & 1 \\ 1 & 1 & 0\end{array}\right|\) \(=\hat{\mathbf{i}}(-1)-\hat{\mathbf{j}}(-1)+\hat{\mathbf{k}}(1-1)\)…
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