TS EAMCET · Maths · Matrices
If \(A=\left[\begin{array}{lll}1 & 2 & 3 \\ 1 & 3 & 5 \\ 2 & 1 & 6\end{array}\right]\), then \((\operatorname{Adj}(\operatorname{Adj} A))^{-1}=\)
- A \(\frac{1}{6}\left[\begin{array}{ccc}8 & -6 & 3 \\ 5 & 1 & -2 \\ -5 & 3 & 1\end{array}\right]\)
- B \(\frac{1}{6}\left[\begin{array}{ccc}13 & -9 & 1 \\ 4 & 0 & -2 \\ -5 & 3 & 1\end{array}\right]\)
- C \(\frac{1}{36}\left[\begin{array}{ccc}13 & -9 & 1 \\ 4 & 0 & -2 \\ -5 & 3 & 1\end{array}\right]\)
- D \(\frac{1}{12}\left[\begin{array}{ccc}4 & -3 & 2 \\ 3 & 4 & 2 \\ -5 & 2 & 1\end{array}\right]\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{36}\left[\begin{array}{ccc}13 & -9 & 1 \\ 4 & 0 & -2 \\ -5 & 3 & 1\end{array}\right]\)
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