TS EAMCET · Maths · Straight Lines
If \(\mathrm{A}(1,1), \mathrm{B}(-1,1)\) and \(\mathrm{C}(-1,-1)\) are three points and a point \(\mathrm{P}\) moves such that \(\mathrm{PA}^2=\mathrm{PB}^2+\mathrm{PC}^2\), then the equation of the locus of \(\mathrm{P}\) is
- A \(x^2+y^2-6 x-2 y+2=0\)
- B \(x^2+y^2+6 x+2 y+2=0\)
- C \(x^2+y^2+6 x-2 y+2=0\)
- D \(x^2+y^2+6 x+2 y-2=0\)
Answer & Solution
Correct Answer
(B) \(x^2+y^2+6 x+2 y+2=0\)
Step-by-step Solution
Detailed explanation
Given \(\mathrm{A}(1,1), \mathrm{B}(-11)\) and \(\mathrm{C}(-1,-1)\) are three points. Let \(\mathrm{P}(\mathrm{x}, \mathrm{y})\) Now, locus of \(\mathrm{PA}^2=\mathrm{PB}^2+\mathrm{PC}^2\) is…
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