TS EAMCET · Maths · Application of Derivatives
An angle between the curves \(x^2-y^2=4\) and \(x^2+y^2=4 \sqrt{2}\) is
- A \(\frac{\pi}{2}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{3}\)
- D \(\frac{\pi}{6}\)
Answer & Solution
Correct Answer
(D) \(\frac{\pi}{6}\)
Step-by-step Solution
Detailed explanation
Equation of given curves, \(x^2-y^2=4\) and \(x^2+y^2=4 \sqrt{2}\) Let \(\left(x_0, y_0\right)\) be point of intersection. \(\therefore\) Angle between curves \(=\) Angle between tangent at point of intersection. Now, \(x^2-y^2=4\) Differentiate w.r.t. ' \(x\) '…
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