TS EAMCET · Maths · Quadratic Equation
If 3 is a root of \(x^2+k x-24=0\). It is also a root of
- A \(x^2+5 x+k=0\)
- B \(x^2+k x+24=0\)
- C \(x^2-k x+6=0\)
- D \(x^2-5 x+k=0\)
Answer & Solution
Correct Answer
(C) \(x^2-k x+6=0\)
Step-by-step Solution
Detailed explanation
We have, 3 is the roots of \(x^2+k x-24=0\) Then, \(9+3 k-24=0\) \[ 3 k=15 \Rightarrow k=5 \] Also, \(x^2-k x+6=0\) \[ 9-3 x+6=0 \Rightarrow k=5 \] Thus 3 is also the root of \(x^2-k x+6=0\)
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