TS EAMCET · Maths · Quadratic Equation
If \(\sin 2 \theta\) and \(\cos 2 \theta\) are solutions of \(x^2+b x-c=0\), then
- A \(b^2+2 c+1=0\)
- B \(b^2+2 c-1=0\)
- C \(b^2-2 c+1=0\)
- D \(b^2-2 c-1=0\)
Answer & Solution
Correct Answer
(B) \(b^2+2 c-1=0\)
Step-by-step Solution
Detailed explanation
According to given informations \(\sin 2 \theta+\cos 2 \theta=-b\) and \(\sin 2 \theta \cos 2 \theta=-c\) \(\because(\sin 2 \theta+\cos 2 \theta)^2=\sin ^2 2 \theta+\cos ^2 2 \theta+2 \sin 2 \theta \cos 2 \theta\)…
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