TS EAMCET · Maths · Complex Number
If \(1-i\) is a root of the equation \(x^2+a x+b=0\) then \(b\) is equal to
- A \(1\)
- B \(-1\)
- C \(-2\)
- D \(2\)
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
Since \(1-i\) is a ront of the equation \(x^2+9 x+b=0\) then another root will be \(1+i\), also, product of roots \(=b\) \[ \begin{array}{rlrl} \Rightarrow & & (1+i)(1-i) & =b \\ \Rightarrow & 1+1 & =b \Rightarrow b=2 \end{array} \]
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