TS EAMCET · Maths · Complex Number
If \(1, \alpha_1, \alpha_2, \alpha_3, \ldots \ldots \alpha_{n-1}\) are \(n^{\text {th }}\) roots of unity then \(\sum_{1 \leq i < j \leq n-1} \alpha_i \alpha_j=\)
- A 1
- B 0
- C -1
- D \(i\)
Answer & Solution
Correct Answer
(A) 1
Step-by-step Solution
Detailed explanation
We have, \(1, \alpha_1, \alpha_2, \alpha_3, \ldots \ldots \alpha_n\), are \(n^{\text {th }}\) root of unity. \[ \Rightarrow \mathrm{x}^{\mathrm{n}}=1 \] So, sum of roots is 0…
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