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TS EAMCET · Maths · Complex Number

If \(1, \alpha_1, \alpha_2, \alpha_3, \ldots \ldots \alpha_{n-1}\) are \(n^{\text {th }}\) roots of unity then \(\sum_{1 \leq i < j \leq n-1} \alpha_i \alpha_j=\)

  1. A 1
  2. B 0
  3. C -1
  4. D \(i\)
Verified Solution

Answer & Solution

Correct Answer

(A) 1

Step-by-step Solution

Detailed explanation

We have, \(1, \alpha_1, \alpha_2, \alpha_3, \ldots \ldots \alpha_n\), are \(n^{\text {th }}\) root of unity. \[ \Rightarrow \mathrm{x}^{\mathrm{n}}=1 \] So, sum of roots is 0…