TS EAMCET · Maths · Hyperbola
For the hyperbola \(x^2-y^2-4 x+2 y+c=0\), if the focus is \(S(2+2 \sqrt{2}, k)\) and the directrix that is adjacent to \(S\) is \(x=2+\sqrt{2}\), then \(c=\)
- A 0
- B -1
- C 1
- D 2
Answer & Solution
Correct Answer
(B) -1
Step-by-step Solution
Detailed explanation
Given hyperbola \(\begin{aligned} x^2-y^2-4 x+2 y+c & =0 \\ (x-2)^2-(y-1)^2 & =3-c \\ \frac{(x-2)^2}{3-c}-\frac{(y-1)^2}{3-c} & =1 \end{aligned}\) Focus of hyperbola is…
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