TS EAMCET · Chemistry · Electrochemistry
At \(25^{\circ} \mathrm{C}\), the molar conductances at infinite dilution for the strong electrolytes \(\mathrm{NaOH}, \mathrm{NaCl}\) and \(\mathrm{BaCl}_2\) are \(248 \times 10^{-4}, 126 \times 10^{-4}\) and \(280 \times 10^{-4} \mathrm{Sm}^2 \mathrm{~mol}^{-1}\) respectively, \(\lambda_m^{\circ} \mathrm{Ba}(\mathrm{OH})_2\) in \(\mathrm{Sm}^2 \mathrm{~mol}^{-1}\) is
- A \(52.4 \times 10^{-4}\)
- B \(524 \times 10^{-4}\)
- C \(402 \times 10^{-4}\)
- D \(262 \times 10^{-4}\)
Answer & Solution
Correct Answer
(B) \(524 \times 10^{-4}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \mathrm{BaCl}_2+2 \mathrm{NaOH} \longrightarrow \mathrm{Ba}(\mathrm{OH})_2+2 \mathrm{NaCl} \\ & \lambda_{m \mathrm{Ba}(\mathrm{OH})_2}^{\infty}=\lambda_{m \mathrm{BaCl}_2}^{\infty}+2 \lambda_{m \mathrm{NaOH}}^{\infty}-2 \lambda_{m…
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