TS EAMCET · Maths · Pair of Lines
For \(c \neq 0, c \neq 1\) if the straight lines \(x+y=1,2 x-y=c\) and \(b x+2 b y=c\) have one common point, then
- A \(c < 1 \Rightarrow b \in\left(-3, \frac{3}{4}\right)\)
- B \(c>1 \Rightarrow b \in\left(-\frac{3}{4}, 3\right)\)
- C \(c < 1 \Rightarrow b \in\left(-3, \frac{3}{2}\right)\)
- D \(c>1 \Rightarrow b \in\left(-\frac{3}{4}, \frac{3}{4}\right)\)
Answer & Solution
Correct Answer
(A) \(c < 1 \Rightarrow b \in\left(-3, \frac{3}{4}\right)\)
Step-by-step Solution
Detailed explanation
We have, \[ x+y-1=0,2 x-y-c=0 \text { and } b x+2 b y-c=0 \] Since above lines have one common point, therefore. These lines are concurrent. So,…
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