TS EAMCET · Maths · Circle
Consider the following statements. I. The intercept made by the circle \(x^2+y^2-2 x-4 y+1=0\) on \(Y\)-axis is \(2 \sqrt{3}\) II. The intercept made by the circle \(x^2+y^2-4 x-2 y+6=0\) on \(X\)-axis is \(2 \sqrt{2}\) III. The straight line \(y=2 x+1\) cuts the circle \(x^2+y^2=9\) at two distinct points Then which one of the following options is correct? 
- A (a)
- B (b)
- C (c)
- D (d)
Answer & Solution
Correct Answer
(C) (c)
Step-by-step Solution
Detailed explanation
(I) \(x^2+y^2-2 x-4 y+1=0\) intercept on \(Y\)-axis is \(2 \sqrt{f^2-c} \Rightarrow 2 \sqrt{4-1} \Rightarrow 2 \sqrt{3}\) True (II) \(x^2+y^2-4 x-2 y-6=0\) intercept on \(X\)-axis \(2 \sqrt{4+6} \Rightarrow 2 \sqrt{10} \neq 2 \sqrt{2}\) False (III) Line \(y=2 x+1\) at the circle…
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