TS EAMCET · Maths · Functions
All the values of \(x\) satisfying the equation \(2 \tan ^1 2 x=\sin 1\left(\frac{4 x}{1+4 x^2}\right)\) lie in the interval
- A \(\left[-\frac{1}{2}, \frac{1}{2}\right]\)
- B \([-1,1]\)
- C \(\left[\frac{1}{2} \infty\right)\)
- D \(\left[-\infty,-\frac{1}{2}\right)\)
Answer & Solution
Correct Answer
(A) \(\left[-\frac{1}{2}, \frac{1}{2}\right]\)
Step-by-step Solution
Detailed explanation
We have, \(\sin ^{-1}\left(\frac{4 x}{1+4 x^2}\right) \Rightarrow \sin ^{-1}\left(\frac{2(2 x)}{1+(2 x)^2}\right)\)…
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