TS EAMCET · Maths · Straight Lines
Let \(C\) be a curve \(a x^2+2 h x y+b y^2+2 g x+2 f y+c=0\) in \(a\) cartesian plane. By rotating the coordinate axes through an angle \(\frac{\pi}{4}\) in the positive direction, if the transformed equation of \(C\) is \(Y^2+X Y-X=0\), then \(\left(h^2-a b\right)-2 g f=\)
- A 0
- B 2
- C 1
- D -1
Answer & Solution
Correct Answer
(A) 0
Step-by-step Solution
Detailed explanation
Equation of given curve \(C\) is \(a x^2+2 h x y+b y^2+2 g x+2 f y+c=0\) \(\ldots(\mathrm{i})\) Now, on rotating the axes through an angle \(\frac{\pi}{4}\) in the positive direction, so we should replace \(x\) by…
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