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TS EAMCET · Maths · Probability

A number \(n\) is chosen at random from the natural numbers 2 to 1001 . The probability that \(n\) is a number that leaves remainder 1 when divided by 7 , is

  1. A \(\frac{73}{500}\)
  2. B \(\frac{71}{1000}\)
  3. C \(\frac{143}{1000}\)
  4. D \(\frac{71}{500}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{71}{500}\)

Step-by-step Solution

Detailed explanation

Total number of numbers from 2 to \(1001=1000\) Now, the numbers, which leaves remainder 1 when divided by 7 , are \(8,15,22, \ldots, 995\). Let these are \(m\) in counting, then we have…