TS EAMCET · Maths · Probability
A number \(n\) is chosen at random from \(S=\{1,2,3, \ldots, 50\}\). Let \(A=\left\{n \in S: n+\frac{50}{n}>27\right\}, B=\{n \in S: n\) is a prime) and \(C=\{n \in S: n\) is a square). Then, correct order of their probabilities is
- A \(P(A) < P(B) < P(C)\)
- B \(P(A)>P(B)>P(C)\)
- C \(P(B) < P(A) < P(C)\)
- D \(P(A)>P(C)>P(B)\)
Answer & Solution
Correct Answer
(B) \(P(A)>P(B)>P(C)\)
Step-by-step Solution
Detailed explanation
Given that \(S=\{1,2,3 \ldots, 50\}\)…
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