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TS EAMCET · Maths · Probability

A number \(n\) is chosen at random from \(S=\{1,2,3, \ldots, 50\}\). Let \(A=\left\{n \in S: n+\frac{50}{n}>27\right\}, B=\{n \in S: n\) is a prime) and \(C=\{n \in S: n\) is a square). Then, correct order of their probabilities is

  1. A \(P(A) < P(B) < P(C)\)
  2. B \(P(A)>P(B)>P(C)\)
  3. C \(P(B) < P(A) < P(C)\)
  4. D \(P(A)>P(C)>P(B)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(P(A)>P(B)>P(C)\)

Step-by-step Solution

Detailed explanation

Given that \(S=\{1,2,3 \ldots, 50\}\)…