TS EAMCET · Maths · Probability
A dealer gets refrigerators from 3 different manufacturing companies \(C_1, C_2\) and \(C_3 .25 \%\) of his stock is from \(C_1, 35 \%\) from \(C_2\) and \(40 \%\) from \(C_3\). The percentages of receiving defective refrigerators from \(C_1, C_2\) and \(C_3\) are \(3 \%, 2 \%\), \(1 \%\) respectively. If a refrigerator sold at random is found to be defective by a customer, then the probability that it is from \(C_2\) is
- A \(\frac{29}{37}\)
- B \(\frac{8}{37}\)
- C \(\frac{14}{37}\)
- D \(\frac{15}{37}\)
Answer & Solution
Correct Answer
(C) \(\frac{14}{37}\)
Step-by-step Solution
Detailed explanation
\(P\left(C_1\right)=0.25 ; P\left(C_2\right)=0.35 ; P\left(C_3\right)=0.4\) Let \(D\) be the case that a defective item is found…
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