TS EAMCET · Chemistry · States of Matter
A balloon filled with an air sample occupies \(3 \mathrm{~L}\) volume at \(35^{\circ} \mathrm{C}\). On lowering the temperature to \(T\), the volume decreases to \(2.5 \mathrm{~L}\). The temperature \(T\) is? [Assume \(p\)-constant]
- A \(16^{\circ} \mathrm{C}\)
- B \(-16^{\circ} \mathrm{C}\)
- C \(24^{\circ} \mathrm{C}\)
- D \(-20^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(B) \(-16^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
\begin{array}{rlrl} V_1 & =3 \mathrm{~L} & & T_1=273+35=308 \mathrm{~K} \\ V_2 & =2.5 \mathrm{~L} & & T_2=? \\ \frac{V_1}{T_1} & =\frac{V_2}{T_2} & & (\text { Charle's law }) \\ \frac{3}{308} & =\frac{2.5}{T_2} & & \\ T_2 & =\frac{2.5 \times 308}{3} & & \\ & =256.6 \mathrm{~K}…
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