TS EAMCET · Maths · Probability
A bag \(P\) contains 3 blue and 5 red balls. Another bag \(Q\) contains 4 blue and 6 red balls. A ball is drawn at random from one of the bags and is found to be red. The probability that it is from bag \(Q\) is
- A \(\frac{24}{49}\)
- B \(\frac{28}{49}\)
- C \(\frac{36}{49}\)
- D \(\frac{42}{49}\)
Answer & Solution
Correct Answer
(A) \(\frac{24}{49}\)
Step-by-step Solution
Detailed explanation
Let \(B_1\) : The event of selecting bag \(P\) \(B_2\) : The event of selecting bag \(Q\) \(A\) : The event of drawing red ball \(\therefore\) Required probability \(=P\left(E_2 / A\right)\)…
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