TS EAMCET · Maths · Inverse Trigonometric Functions
\(2 \tan \mathrm{h}^{-1} \frac{1}{2}\) is equal to
- A 0
- B \(\log 2\)
- C \(\log 3\)
- D \(\log 4\)
Answer & Solution
Correct Answer
(C) \(\log 3\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} 2 \tanh ^{-1} & \left(\frac{1}{2}\right) \\ & =\tanh ^{-1} \frac{2\left(\frac{1}{2}\right)}{1+\left(\frac{1}{2}\right)^2} \\ & {\left[\because 2 \tanh ^{-1} x=\tanh ^{-1} \frac{2 x}{1+x^2}\right] }\end{aligned}\)…
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