TS EAMCET · Maths · Trigonometric Ratios & Identities
\(\sin 120^{\circ} \cos 150^{\circ}-\cos 240^{\circ} \sin 330^{\circ}\) is equal to :
- A 1
- B -1
- C \(\frac{2}{3}\)
- D \(-\left(\frac{\sqrt{3}+1}{4}\right)\)
Answer & Solution
Correct Answer
(B) -1
Step-by-step Solution
Detailed explanation
\(\sin 120^{\circ} \cos 150^{\circ}-\cos 240^{\circ} \sin 330^{\circ}\) \(=-\cos 30^{\circ} \sin 60^{\circ}-\cos 60^{\circ} \sin 30^{\circ}\) \(=-\left(\sin 60^{\circ} \cos 30^{\circ}+\cos 60^{\circ} \sin 30^{\circ}\right)\)…
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