TS EAMCET · Maths · Sequences and Series
\(\frac{1}{3.6}+\frac{1}{6.9}+\frac{1}{9.12}+\ldots . \text { to } 9 \text { terms }=\)
- A \(\frac{10}{99}\)
- B \(\frac{11}{108}\)
- C \(\frac{1}{10}\)
- D \(\frac{1}{90}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{10}\)
Step-by-step Solution
Detailed explanation
Let \(S=\frac{1}{3 \cdot 6}+\frac{1}{6 \cdot 9}+\frac{1}{9 \cdot 12}+\ldots \ldots\) to 9 terms…
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