TS EAMCET · Chemistry · d and f Block Elements
Which of the following orders is correct for the property given?
- A \(\mathrm{Cr} \lt \mathrm{Mn} \lt \mathrm{Fe}\) - standard electrode potential value of \(\mathrm{M}^{3+} / \mathrm{M}^{2+}\)
- B \(\mathrm{Cr}^{2+} \lt \mathrm{Mn}^{2+} \lt \mathrm{Fe}^{2+}-\) magnetic moments
- C \(\mathrm{VO}_2^{+} \lt \mathrm{Cr}_2 \mathrm{O}_7^{2-} \lt \mathrm{MnO}_4^{-}\)- oxidizing power
- D \(\mathrm{Ti} \lt \mathrm{V} \lt \mathrm{Cr}\) - first ionization enthalpy.
Answer & Solution
Correct Answer
(C) \(\mathrm{VO}_2^{+} \lt \mathrm{Cr}_2 \mathrm{O}_7^{2-} \lt \mathrm{MnO}_4^{-}\)- oxidizing power
Step-by-step Solution
Detailed explanation
Standard electrode potential value for \(\mathrm{M}^{3+} / \mathrm{M}^{2+}\) is \(\mathrm{Mn}\gt\mathrm{Fe}\gt\mathrm{Cr}\). Magnetic moment \((\mu)=\sqrt{\mathrm{n}(\mathrm{n}+2}\) \(\mathrm{n}=\) no. of unpaired electron. So \(\mathrm{Mn}^{2+}=3 \mathrm{~d}^5=5\) unpaired…
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