TS EAMCET · Chemistry · Chemical Bonding and Molecular Structure
The bond order of \(\mathrm{O}_2^{+}\)is \(\mathrm{x}\). The bond orders of \(\mathrm{O}_2^{-}\)and \(\mathrm{O}_2^{2+}\) are respectively
- A \(\frac{5}{3} x, \frac{5}{6} x\)
- B \(\frac{3}{5} x, \frac{6}{5} x\)
- C \(\frac{2}{5} x, \frac{3}{5} x\)
- D \(\frac{5}{2} x, \frac{5}{3} x\)
Answer & Solution
Correct Answer
(B) \(\frac{3}{5} x, \frac{6}{5} x\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \quad \text { B.O }=\frac{\mathrm{N}_{\mathrm{b}}-\mathrm{Na}}{2} \\ & \text { For } \mathrm{O}_2^{+}=\sigma 1 \mathrm{~s}^2 \sigma^* 1 \mathrm{~s}^2 \sigma 2 \mathrm{~s}^2 \sigma^* 2 \mathrm{~s}^2 \sigma 2 \mathrm{p}_{\mathrm{z}}^2 \pi 2…
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