TS EAMCET · Chemistry · Chemical Kinetics
What is the unit for the zero order rate constant?
- A \(\mathrm{L}^{-1} \mathrm{~mol} \mathrm{~s}^{-1}\)
- B \(\mathrm{L} \mathrm{mol} \mathrm{s}^{-1}\)
- C \(\mathrm{L} \mathrm{mol}^{-1} \mathrm{~s}^{-1}\)
- D \(\mathrm{L}^2 \mathrm{~mol}^{-2} \mathrm{~s}^{-1}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{L}^{-1} \mathrm{~mol} \mathrm{~s}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\because\) Rate \((r)=\) rate constant \((k)\) [conc. \(]^{\text {order }}\) \(k=\frac{\text { rate }}{[\text { conc. }]^{\text {order }(=n)}}=\frac{\mathrm{mol} \mathrm{L}^{-1}}{\left[\mathrm{~mol} \mathrm{~L}^{-1}\right]^n}\) where, \(n=\) order of reaction…
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