TS EAMCET · Chemistry · d and f Block Elements
What is the correct order of spin only magnetic moment (in BM) of \(\mathrm{Mn}^{2+}, \mathrm{Cr}^{2+}\) and \(\mathrm{V}^{2+}\) ?
- A \(\mathrm{Mn}^{2+}>\mathrm{V}^{2+}>\mathrm{Cr}^{2+}\)
- B \(\mathrm{V}^{2+}>\mathrm{Cr}^{2+}>\mathrm{Mn}^{2+}\)
- C \(\mathrm{Mn}^{2+}>\mathrm{Cr}^{2+}>\mathrm{V}^{2+}\)
- D \(\mathrm{Cr}^{2+}>\mathrm{V}^{2+}>\mathrm{Mn}^{2+}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{Mn}^{2+}>\mathrm{Cr}^{2+}>\mathrm{V}^{2+}\)
Step-by-step Solution
Detailed explanation
Spin only magnetic moments depend upon the number of unpaired electrons, more the number of unpaired electron, greater will be the spin only magnetic moment. \({ }_{25} \mathrm{Mn}=1 s^2, 2 s^2 2 p^6, 3 s^2 3 p^6 3 d^5, 4 s^2\)…
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